50 kva transformer max current single phase
The **maximum rated current** of a 50 kVA single-phase transformer depends on the **voltage level**, and the calculation formula is:
**Current (A) = Capacity (VA) ÷ Voltage (V)**
I. Current Calculation of Single-phase Transformer (50 kVA)
Voltage Level (V) | Calculation Formula | Maximum Current (A) | Application Scenarios |
120V | 50,000 ÷ 120 | 416.67 A | Low-voltage and small-power equipment |
240V | 50,000 ÷240 | 208.33 A | Household/small commercial power supply (common in the United States) |
480V | 50,000 ÷480 | 104.17 A | Industrial single-phase equipment |
600V | 50,000 ÷600 | 83.33 A | High-voltage industrial systems |
II. Key Precautions
1. **Explanation of the Formula**:
- The apparent power (kVA) of a single-phase transformer = Voltage (V) × Current (A), so the current is **inversely
proportional** to the voltage.
- **There is no need to consider the power factor** (kVA already includes the apparent power).
2. **Commonly Used Voltages in the United States**:
- **120/240V Split Phase** (Single-phase three-wire system):
- The current of the 240V winding is **208.33 A**, and the current of the 120V winding is **416.67 A** (the load needs
to be balanced).
- **480V Single-phase**: Commonly found in industrial equipment (such as welding machines).
3. **Overload Capacity**:
- The transformer allows **short-term overload** (such as 10% to 20%), but **it must not exceed the rated current during
continuous operation**, otherwise it will be damaged due to overheating.
III. Selection and Application Suggestions
- **Household/Commercial Scenarios** (240V):
- Select a circuit breaker **above 208 A** (such as 225A), and match it with a #2/0 AWG copper cable (current-carrying
capacity 215A).
- **Industrial Equipment** (480V):
- With a current of 104 A, a 125A circuit breaker can be selected, and it is paired with a #1 AWG copper cable (current-carrying
capacity 130A).
- **Voltage Matching**:
- Be sure to confirm that the **rated voltage on the nameplate** of the transformer is consistent with the system (for example,
for an isolation transformer with a 480V input and a 240V output, the current on the secondary side is 208A).
**Example**:
If the transformer is a **50 kVA, 240V single-phase** one, then the maximum continuous current is **208.33 A**, which is marked
as **208 A** (rounded off).