Calculation Formulas for Voltage Drop
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1. **Calculation Formula for Voltage Drop in DC Circuits**
- For a DC circuit with pure resistance, according to Ohm's Law \(U = IR\), where \(U\) is the voltage drop (in volts, V), \(I\) is the current (in amperes, A), and \(R\) is the resistance (in ohms, \(\Omega\)).
- For example, in a DC circuit, if the resistance \(R = 10\Omega\) and the current \(I = 2A\), then according to the formula, the voltage drop \(U = IR = 2A\times10\Omega = 20V\).
2. **Calculation Formula for Voltage Drop in AC Single-Phase Circuits (Considering Resistance and Inductance)**
- For an AC single-phase circuit, the calculation formula for voltage drop is \(\Delta U = I\times(Z)\), where \(Z\) is the line impedance (in ohms, \(\Omega\)) and \(I\) is the current (in amperes, A).
- The line impedance \(Z=\sqrt{R^{2}+X_{L}^{2}}\), where \(R\) is the line resistance and \(X_{L}= 2\pi fL\) is the inductive reactance (\(f\) is the frequency of the alternating current, in hertz, Hz; \(L\) is the inductance, in henries, H).
- Suppose there is an AC single-phase circuit with a current \(I = 5A\), a line resistance \(R = 3\Omega\), an inductance \(L = 0.02H\), and a frequency \(f = 50Hz\). First, calculate the inductive reactance \(X_{L}=2\pi fL = 2\times3.14\times50Hz\times0.02H\approx 6.28\Omega\). Then calculate the line impedance \(Z=\sqrt{R^{2}+X_{L}^{2}}=\sqrt{3^{2}+6.28^{2}}\Omega\approx 6.96\Omega\). Finally, calculate the voltage drop \(\Delta U = I\times Z = 5A\times6.96\Omega\approx34.8V\).
3. **Calculation Formulas for Voltage Drop in AC Three-Phase Circuits (Taking Three-Phase Balanced Loads as an Example)**
- For an AC three-phase circuit with a three-phase balanced load, the calculation formula for line voltage drop is \(\Delta U_{L}=\sqrt{3}I\times Z\), and the calculation formula for phase voltage drop is \(\Delta U_{P}=I\times Z\).
- Here, \(I\) is the line current (in amperes, A), and \(Z\) is the impedance per phase of the line (in ohms, \(\Omega\)).
- For example, in a three-phase balanced AC circuit, if the line current \(I = 10A\) and the impedance per phase of the line \(Z = 2\Omega\), calculate the line voltage drop \(\Delta U_{L}=\sqrt{3}I\times Z=\sqrt{3}\times10A\times2\Omega\approx 34.64V\), and the phase voltage drop \(\Delta U_{P}=I\times Z = 10A\times2\Omega = 20V\).#TransformerTechnology #CopperFoilWinding #PowerTransformers #EngineeringTechniques #ElectricalComponents #EfficientWinding#PowerTransformers #TransformerManufacturing #ElectricalComponents #EngineeringExplained #wankongtransformer #transformador #eléctrico #tecnología #fábrica #foryou #viral #videocorto #manufactura #máquina #energía #shorts #tendencias #cableado #trabajofábrica #ingenieríaeléctrica #transformadordeenergía #transformadoreléctrico #fabricación #proceso #fabricante #procesodefabricación #EnvolturaAltaTensión #EEUU #Canadá #Australia #ReinoUnido #vlogdiario #diario #trabajoadistinta #Tesla #TrabajoDiario #cableeléctrico #ingenieríadeenergía #transformador #envolturaenfoil #naciónbajavoltage #ingenieríaeléctrica #EnvolturaBajavoltage #EnvolturaFoil